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Theorem mopick2 1983
Description: "At most one" can show the existence of a common value. In this case we can infer existence of conjunction from a conjunction of existence, and it is one way to achieve the converse of 19.40 1522. (Contributed by NM, 5-Apr-2004.) (Proof shortened by Andrew Salmon, 9-Jul-2011.)
Assertion
Ref Expression
mopick2  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps )  /\  E. x
( ph  /\  ch )
)  ->  E. x
( ph  /\  ps  /\  ch ) )

Proof of Theorem mopick2
StepHypRef Expression
1 hbmo1 1938 . . . 4  |-  ( E* x ph  ->  A. x E* x ph )
2 hbe1 1384 . . . 4  |-  ( E. x ( ph  /\  ps )  ->  A. x E. x ( ph  /\  ps ) )
31, 2hban 1439 . . 3  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  A. x
( E* x ph  /\ 
E. x ( ph  /\ 
ps ) ) )
4 mopick 1978 . . . . . 6  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  ( ph  ->  ps ) )
54ancld 308 . . . . 5  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  ( ph  ->  ( ph  /\  ps ) ) )
65anim1d 319 . . . 4  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  (
( ph  /\  ch )  ->  ( ( ph  /\  ps )  /\  ch )
) )
7 df-3an 887 . . . 4  |-  ( (
ph  /\  ps  /\  ch ) 
<->  ( ( ph  /\  ps )  /\  ch )
)
86, 7syl6ibr 151 . . 3  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  (
( ph  /\  ch )  ->  ( ph  /\  ps  /\ 
ch ) ) )
93, 8eximdh 1502 . 2  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps ) )  ->  ( E. x ( ph  /\  ch )  ->  E. x
( ph  /\  ps  /\  ch ) ) )
1093impia 1101 1  |-  ( ( E* x ph  /\  E. x ( ph  /\  ps )  /\  E. x
( ph  /\  ch )
)  ->  E. x
( ph  /\  ps  /\  ch ) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 97    /\ w3a 885   E.wex 1381   E*wmo 1901
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428
This theorem depends on definitions:  df-bi 110  df-3an 887  df-nf 1350  df-sb 1646  df-eu 1903  df-mo 1904
This theorem is referenced by: (None)
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