Theorem eldifsni 3496

Description: Membership in a set with an element removed. (Contributed by NM, 10-Mar-2015.)

Assertion

Ref	Expression
eldifsni	|- ( A e. ( B \ { C } ) -> A =/= C )

Proof of Theorem eldifsni

Step	Hyp	Ref	Expression
1		eldifsn 3495	. 2 |- ( A e. ( B \ { C } ) <-> ( A e. B /\ A =/= C ) )
2	1	simprbi 260	1 |- ( A e. ( B \ { C } ) -> A =/= C )

Syntax hints:   -> wi 4   e. wcel 1393   =/= wne 2204   \ cdif 2914   {csn 3375

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-in1 544  ax-in2 545  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022

This theorem depends on definitions:  df-bi 110  df-tru 1246  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-nfc 2167  df-ne 2206  df-v 2559  df-dif 2920  df-sn 3381

This theorem is referenced by:  neldifsn  3497  suppssfv  5708  suppssov1  5709