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Theorem pwssunim 4021
Description: The power class of the union of two classes is a subset of the union of their power classes, if one class is a subclass of the other. One direction of Exercise 4.12(l) of [Mendelson] p. 235. (Contributed by Jim Kingdon, 30-Sep-2018.)
Assertion
Ref Expression
pwssunim ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))

Proof of Theorem pwssunim
StepHypRef Expression
1 ssequn2 3116 . . . . 5 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐴)
2 pweq 3362 . . . . . 6 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) = 𝒫 𝐴)
3 eqimss 2997 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
42, 3syl 14 . . . . 5 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
51, 4sylbi 114 . . . 4 (𝐵𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
6 ssequn1 3113 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐵)
7 pweq 3362 . . . . . 6 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) = 𝒫 𝐵)
8 eqimss 2997 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
97, 8syl 14 . . . . 5 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
106, 9sylbi 114 . . . 4 (𝐴𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
115, 10orim12i 676 . . 3 ((𝐵𝐴𝐴𝐵) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
1211orcoms 649 . 2 ((𝐴𝐵𝐵𝐴) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
13 ssun 3122 . 2 ((𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
1412, 13syl 14 1 ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4  wo 629   = wceq 1243  cun 2915  wss 2917  𝒫 cpw 3359
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022
This theorem depends on definitions:  df-bi 110  df-tru 1246  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-nfc 2167  df-v 2559  df-un 2922  df-in 2924  df-ss 2931  df-pw 3361
This theorem is referenced by:  pwunim  4023
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