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Mirrors > Home > ILE Home > Th. List > anandis | GIF version |
Description: Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.) |
Ref | Expression |
---|---|
anandis.1 | ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜏) |
Ref | Expression |
---|---|
anandis | ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | anandis.1 | . . 3 ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜏) | |
2 | 1 | an4s 522 | . 2 ⊢ (((𝜑 ∧ 𝜑) ∧ (𝜓 ∧ 𝜒)) → 𝜏) |
3 | 2 | anabsan 509 | 1 ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∧ wa 97 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 99 ax-ia2 100 ax-ia3 101 |
This theorem depends on definitions: df-bi 110 |
This theorem is referenced by: 3impdi 1190 dff13 5407 f1oiso 5465 ltapig 6436 ltmpig 6437 |
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