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Theorem anabsan 509
Description: Absorption of antecedent with conjunction. (Contributed by NM, 24-Mar-1996.) (Revised by NM, 18-Nov-2013.)
Hypothesis
Ref Expression
anabsan.1 (((𝜑𝜑) ∧ 𝜓) → 𝜒)
Assertion
Ref Expression
anabsan ((𝜑𝜓) → 𝜒)

Proof of Theorem anabsan
StepHypRef Expression
1 pm4.24 375 . 2 (𝜑 ↔ (𝜑𝜑))
2 anabsan.1 . 2 (((𝜑𝜑) ∧ 𝜓) → 𝜒)
31, 2sylanb 268 1 ((𝜑𝜓) → 𝜒)
Colors of variables: wff set class
Syntax hints:  wi 4  wa 97
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101
This theorem depends on definitions:  df-bi 110
This theorem is referenced by:  anabss1  510  anabss5  512  anandis  526
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