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Theorem disj4im 3276
Description: A consequence of two classes being disjoint. In classical logic this would be a biconditional. (Contributed by Jim Kingdon, 2-Aug-2018.)
Assertion
Ref Expression
disj4im ((𝐴𝐵) = ∅ → ¬ (𝐴𝐵) ⊊ 𝐴)

Proof of Theorem disj4im
StepHypRef Expression
1 disj3 3272 . . 3 ((𝐴𝐵) = ∅ ↔ 𝐴 = (𝐴𝐵))
2 eqcom 2042 . . 3 (𝐴 = (𝐴𝐵) ↔ (𝐴𝐵) = 𝐴)
31, 2bitri 173 . 2 ((𝐴𝐵) = ∅ ↔ (𝐴𝐵) = 𝐴)
4 dfpss2 3029 . . . 4 ((𝐴𝐵) ⊊ 𝐴 ↔ ((𝐴𝐵) ⊆ 𝐴 ∧ ¬ (𝐴𝐵) = 𝐴))
54simprbi 260 . . 3 ((𝐴𝐵) ⊊ 𝐴 → ¬ (𝐴𝐵) = 𝐴)
65con2i 557 . 2 ((𝐴𝐵) = 𝐴 → ¬ (𝐴𝐵) ⊊ 𝐴)
73, 6sylbi 114 1 ((𝐴𝐵) = ∅ → ¬ (𝐴𝐵) ⊊ 𝐴)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4   = wceq 1243  cdif 2914  cin 2916  wss 2917  wpss 2918  c0 3224
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-in1 544  ax-in2 545  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022
This theorem depends on definitions:  df-bi 110  df-tru 1246  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-nfc 2167  df-ne 2206  df-ral 2311  df-v 2559  df-dif 2920  df-in 2924  df-pss 2933  df-nul 3225
This theorem is referenced by: (None)
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