Theorem anandi 524

Description: Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995.)

Assertion

Ref	Expression
anandi	⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)))

Proof of Theorem anandi

Step	Hyp	Ref	Expression
1		anidm 376	. . 3 ⊢ ((𝜑 ∧ 𝜑) ↔ 𝜑)
2	1	anbi1i 431	. 2 ⊢ (((𝜑 ∧ 𝜑) ∧ (𝜓 ∧ 𝜒)) ↔ (𝜑 ∧ (𝜓 ∧ 𝜒)))
3		an4 520	. 2 ⊢ (((𝜑 ∧ 𝜑) ∧ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)))
4	2, 3	bitr3i 175	1 ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)))

Syntax hints:   ∧ wa 97   ↔ wb 98

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101

This theorem depends on definitions:  df-bi 110

This theorem is referenced by:  anandi3  898  moanim  1974  difundi  3189  inrab  3209  uniin  3600  xpcom  4864  fin  5076  fndmin  5274  nnaord  6082  ltexprlemdisj  6704