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Theorem bianabs 543
Description: Absorb a hypothesis into the second member of a biconditional. (Contributed by FL, 15-Feb-2007.)
Hypothesis
Ref Expression
bianabs.1 (𝜑 → (𝜓 ↔ (𝜑𝜒)))
Assertion
Ref Expression
bianabs (𝜑 → (𝜓𝜒))

Proof of Theorem bianabs
StepHypRef Expression
1 bianabs.1 . 2 (𝜑 → (𝜓 ↔ (𝜑𝜒)))
2 ibar 285 . 2 (𝜑 → (𝜒 ↔ (𝜑𝜒)))
31, 2bitr4d 180 1 (𝜑 → (𝜓𝜒))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 97  wb 98
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101
This theorem depends on definitions:  df-bi 110
This theorem is referenced by:  ceqsrexv  2671  opelopab2a  3999  ov  5607  ovg  5626  ltresr  6896
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