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Mirrors > Home > ILE Home > Th. List > 3anibar | GIF version |
Description: Remove a hypothesis from the second member of a biimplication. (Contributed by FL, 22-Jul-2008.) |
Ref | Expression |
---|---|
3anibar.1 | ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜃 ↔ (𝜒 ∧ 𝜏))) |
Ref | Expression |
---|---|
3anibar | ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜃 ↔ 𝜏)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | 3anibar.1 | . 2 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜃 ↔ (𝜒 ∧ 𝜏))) | |
2 | simp3 906 | . . 3 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜒) | |
3 | 2 | biantrurd 289 | . 2 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜏 ↔ (𝜒 ∧ 𝜏))) |
4 | 1, 3 | bitr4d 180 | 1 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜃 ↔ 𝜏)) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∧ wa 97 ↔ wb 98 ∧ w3a 885 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 99 ax-ia2 100 ax-ia3 101 |
This theorem depends on definitions: df-bi 110 df-3an 887 |
This theorem is referenced by: frecsuclem3 5990 shftfibg 9421 |
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