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Theorem sseqin2 3474
Description: A relationship between subclass and intersection. Similar to Exercise 9 of [TakeutiZaring] p. 18. (Contributed by NM, 17-May-1994.)
Assertion
Ref Expression
sseqin2 (A B ↔ (BA) = A)

Proof of Theorem sseqin2
StepHypRef Expression
1 dfss1 3460 1 (A B ↔ (BA) = A)
Colors of variables: wff setvar class
Syntax hints:  wb 176   = wceq 1642  cin 3208   wss 3257
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-ss 3259
This theorem is referenced by:  dfss4  3489  resima2  5007  sbthlem1  6203
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