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Theorem rextpg 3778
Description: Convert a quantification over a triple to a disjunction. (Contributed by Mario Carneiro, 23-Apr-2015.)
Hypotheses
Ref Expression
ralprg.1 (x = A → (φψ))
ralprg.2 (x = B → (φχ))
raltpg.3 (x = C → (φθ))
Assertion
Ref Expression
rextpg ((A V B W C X) → (x {A, B, C}φ ↔ (ψ χ θ)))
Distinct variable groups:   x,A   x,B   x,C   ψ,x   χ,x   θ,x
Allowed substitution hints:   φ(x)   V(x)   W(x)   X(x)

Proof of Theorem rextpg
StepHypRef Expression
1 ralprg.1 . . . . . 6 (x = A → (φψ))
2 ralprg.2 . . . . . 6 (x = B → (φχ))
31, 2rexprg 3776 . . . . 5 ((A V B W) → (x {A, B}φ ↔ (ψ χ)))
43orbi1d 683 . . . 4 ((A V B W) → ((x {A, B}φ x {C}φ) ↔ ((ψ χ) x {C}φ)))
5 raltpg.3 . . . . . 6 (x = C → (φθ))
65rexsng 3766 . . . . 5 (C X → (x {C}φθ))
76orbi2d 682 . . . 4 (C X → (((ψ χ) x {C}φ) ↔ ((ψ χ) θ)))
84, 7sylan9bb 680 . . 3 (((A V B W) C X) → ((x {A, B}φ x {C}φ) ↔ ((ψ χ) θ)))
983impa 1146 . 2 ((A V B W C X) → ((x {A, B}φ x {C}φ) ↔ ((ψ χ) θ)))
10 df-tp 3743 . . . 4 {A, B, C} = ({A, B} ∪ {C})
1110rexeqi 2812 . . 3 (x {A, B, C}φx ({A, B} ∪ {C})φ)
12 rexun 3443 . . 3 (x ({A, B} ∪ {C})φ ↔ (x {A, B}φ x {C}φ))
1311, 12bitri 240 . 2 (x {A, B, C}φ ↔ (x {A, B}φ x {C}φ))
14 df-3or 935 . 2 ((ψ χ θ) ↔ ((ψ χ) θ))
159, 13, 143bitr4g 279 1 ((A V B W C X) → (x {A, B, C}φ ↔ (ψ χ θ)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 176   wo 357   wa 358   w3o 933   w3a 934   = wceq 1642   wcel 1710  wrex 2615  cun 3207  {csn 3737  {cpr 3738  {ctp 3739
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3or 935  df-3an 936  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-rex 2620  df-v 2861  df-sbc 3047  df-nin 3211  df-compl 3212  df-un 3214  df-sn 3741  df-pr 3742  df-tp 3743
This theorem is referenced by:  rextp  3782
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