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Theorem xpeq2d 4369
 Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)
Hypothesis
Ref Expression
xpeq1d.1 (𝜑𝐴 = 𝐵)
Assertion
Ref Expression
xpeq2d (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))

Proof of Theorem xpeq2d
StepHypRef Expression
1 xpeq1d.1 . 2 (𝜑𝐴 = 𝐵)
2 xpeq2 4360 . 2 (𝐴 = 𝐵 → (𝐶 × 𝐴) = (𝐶 × 𝐵))
31, 2syl 14 1 (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))
 Colors of variables: wff set class Syntax hints:   → wi 4   = wceq 1243   × cxp 4343 This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-11 1397  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022 This theorem depends on definitions:  df-bi 110  df-tru 1246  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-opab 3819  df-xp 4351 This theorem is referenced by:  csbresg  4615  fconstg  5083  xpsneng  6296  expival  9257
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