Theorem syl2and 279

Description: A syllogism deduction. (Contributed by NM, 15-Dec-2004.)

Hypotheses

Ref	Expression
syl2and.1	⊢ (𝜑 → (𝜓 → 𝜒))
syl2and.2	⊢ (𝜑 → (𝜃 → 𝜏))
syl2and.3	⊢ (𝜑 → ((𝜒 ∧ 𝜏) → 𝜂))

Assertion

Ref	Expression
syl2and	⊢ (𝜑 → ((𝜓 ∧ 𝜃) → 𝜂))

Proof of Theorem syl2and

Step	Hyp	Ref	Expression
1		syl2and.1	. 2 ⊢ (𝜑 → (𝜓 → 𝜒))
2		syl2and.2	. . 3 ⊢ (𝜑 → (𝜃 → 𝜏))
3		syl2and.3	. . 3 ⊢ (𝜑 → ((𝜒 ∧ 𝜏) → 𝜂))
4	2, 3	sylan2d 278	. 2 ⊢ (𝜑 → ((𝜒 ∧ 𝜃) → 𝜂))
5	1, 4	syland 277	1 ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → 𝜂))

Syntax hints:   → wi 4   ∧ wa 97

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101

This theorem depends on definitions:  df-bi 110

This theorem is referenced by:  anim12d  318  recexprlem1ssl  6731  recexprlem1ssu  6732  fzen  8907