Theorem sseq2 2967

Description: Equality theorem for the subclass relationship. (Contributed by NM, 25-Jun-1998.)

Assertion

Ref	Expression
sseq2	⊢ (𝐴 = 𝐵 → (𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵))

Proof of Theorem sseq2

Step	Hyp	Ref	Expression
1		sstr2 2952	. . . 4 ⊢ (𝐶 ⊆ 𝐴 → (𝐴 ⊆ 𝐵 → 𝐶 ⊆ 𝐵))
2	1	com12 27	. . 3 ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵))
3		sstr2 2952	. . . 4 ⊢ (𝐶 ⊆ 𝐵 → (𝐵 ⊆ 𝐴 → 𝐶 ⊆ 𝐴))
4	3	com12 27	. . 3 ⊢ (𝐵 ⊆ 𝐴 → (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴))
5	2, 4	anim12i 321	. 2 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴) → ((𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵) ∧ (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴)))
6		eqss 2960	. 2 ⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴))
7		dfbi2 368	. 2 ⊢ ((𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵) ↔ ((𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵) ∧ (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴)))
8	5, 6, 7	3imtr4i 190	1 ⊢ (𝐴 = 𝐵 → (𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵))

Syntax hints:   → wi 4   ∧ wa 97   ↔ wb 98   = wceq 1243   ⊆ wss 2917

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-11 1397  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022

This theorem depends on definitions:  df-bi 110  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-in 2924  df-ss 2931

This theorem is referenced by:  sseq12  2968  sseq2i  2970  sseq2d  2973  syl5sseq  2993  nssne1  3001  psseq2  3032  sseq0  3258  un00  3263  disjpss  3278  pweq  3362  ssintab  3632  ssintub  3633  intmin  3635  treq  3860  ssexg  3896  frforeq3  4084  frirrg  4087  iunpw  4211  ordtri2orexmid  4248  ontr2exmid  4250  onsucsssucexmid  4252  ordtri2or2exmid  4296  fununi  4967  funcnvuni  4968  feq3  5032  ssimaexg  5235  nnawordex  6101  ereq1  6113  xpiderm  6177  domeng  6233  ssfiexmid  6336  bdssexg  10024  bj-nntrans  10076  bj-omtrans  10081