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Mirrors > Home > ILE Home > Th. List > releqd | GIF version |
Description: Equality deduction for the relation predicate. (Contributed by NM, 8-Mar-2014.) |
Ref | Expression |
---|---|
releqd.1 | ⊢ (𝜑 → 𝐴 = 𝐵) |
Ref | Expression |
---|---|
releqd | ⊢ (𝜑 → (Rel 𝐴 ↔ Rel 𝐵)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | releqd.1 | . 2 ⊢ (𝜑 → 𝐴 = 𝐵) | |
2 | releq 4422 | . 2 ⊢ (𝐴 = 𝐵 → (Rel 𝐴 ↔ Rel 𝐵)) | |
3 | 1, 2 | syl 14 | 1 ⊢ (𝜑 → (Rel 𝐴 ↔ Rel 𝐵)) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ↔ wb 98 = wceq 1243 Rel wrel 4350 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 99 ax-ia2 100 ax-ia3 101 ax-5 1336 ax-7 1337 ax-gen 1338 ax-ie1 1382 ax-ie2 1383 ax-8 1395 ax-11 1397 ax-4 1400 ax-17 1419 ax-i9 1423 ax-ial 1427 ax-i5r 1428 ax-ext 2022 |
This theorem depends on definitions: df-bi 110 df-nf 1350 df-sb 1646 df-clab 2027 df-cleq 2033 df-clel 2036 df-in 2924 df-ss 2931 df-rel 4352 |
This theorem is referenced by: dftpos3 5877 tposfo2 5882 tposf12 5884 |
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