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Theorem errel 6115
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6106 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 919 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1243  cun 2915  wss 2917  ccnv 4344  dom cdm 4345  ccom 4349  Rel wrel 4350   Er wer 6103
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99
This theorem depends on definitions:  df-bi 110  df-3an 887  df-er 6106
This theorem is referenced by:  ercl  6117  ersym  6118  ertr  6121  ercnv  6127  erssxp  6129  erth  6150  iinerm  6178
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