Theorem abssi 3015

Description: Inference of abstraction subclass from implication. (Contributed by NM, 20-Jan-2006.)

Hypothesis

Ref	Expression
abssi.1	⊢ (𝜑 → 𝑥 ∈ 𝐴)

Assertion

Ref	Expression
abssi	⊢ {𝑥 ∣ 𝜑} ⊆ 𝐴

Distinct variable group:   𝑥,𝐴

Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem abssi

Step	Hyp	Ref	Expression
1		abssi.1	. . 3 ⊢ (𝜑 → 𝑥 ∈ 𝐴)
2	1	ss2abi 3012	. 2 ⊢ {𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝑥 ∈ 𝐴}
3		abid2 2158	. 2 ⊢ {𝑥 ∣ 𝑥 ∈ 𝐴} = 𝐴
4	2, 3	sseqtri 2977	1 ⊢ {𝑥 ∣ 𝜑} ⊆ 𝐴

Syntax hints:   → wi 4   ∈ wcel 1393  {cab 2026   ⊆ wss 2917

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022

This theorem depends on definitions:  df-bi 110  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-nfc 2167  df-in 2924  df-ss 2931

This theorem is referenced by:  ssab2  3024  abf  3260  intab  3644  opabss  3821  relopabi  4463  exse2  4699  tfrlem8  5934  frecabex  5984  fiprc  6292  nqprxx  6644  ltnqex  6647  gtnqex  6648  recexprlemell  6720  recexprlemelu  6721  recexprlempr  6730