Theorem 3eqtrrd 2077

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypotheses

Ref	Expression
3eqtrd.1	⊢ (𝜑 → 𝐴 = 𝐵)
3eqtrd.2	⊢ (𝜑 → 𝐵 = 𝐶)
3eqtrd.3	⊢ (𝜑 → 𝐶 = 𝐷)

Assertion

Ref	Expression
3eqtrrd	⊢ (𝜑 → 𝐷 = 𝐴)

Proof of Theorem 3eqtrrd

Step	Hyp	Ref	Expression
1		3eqtrd.1	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
2		3eqtrd.2	. . 3 ⊢ (𝜑 → 𝐵 = 𝐶)
3	1, 2	eqtrd 2072	. 2 ⊢ (𝜑 → 𝐴 = 𝐶)
4		3eqtrd.3	. 2 ⊢ (𝜑 → 𝐶 = 𝐷)
5	3, 4	eqtr2d 2073	1 ⊢ (𝜑 → 𝐷 = 𝐴)

Syntax hints:   → wi 4   = wceq 1243

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-gen 1338  ax-4 1400  ax-17 1419  ax-ext 2022

This theorem depends on definitions:  df-bi 110  df-cleq 2033

This theorem is referenced by:  nnanq0  6556  1idprl  6688  1idpru  6689  axcnre  6955  fseq1p1m1  8956  expmulzap  9301  expubnd  9311  subsq  9358  crim  9458  rereb  9463