Theorem stdpc4 1658

Description: The specialization axiom of standard predicate calculus. It states that if a statement ph holds for all x, then it also holds for the specific case of y (properly) substituted for x. Translated to traditional notation, it can be read: " A. x ph ( x ) -> ph ( y ), provided that y is free for x in ph ( x )." Axiom 4 of [Mendelson] p. 69. (Contributed by NM, 5-Aug-1993.)

Assertion

Ref	Expression
stdpc4	|- ( A. x ph -> [ y / x ] ph )

Proof of Theorem stdpc4

Step	Hyp	Ref	Expression
1		ax-1 5	. . 3 |- ( ph -> ( x = y -> ph ) )
2	1	alimi 1344	. 2 |- ( A. x ph -> A. x ( x = y -> ph ) )
3		sb2 1650	. 2 |- ( A. x ( x = y -> ph ) -> [ y / x ] ph )
4	2, 3	syl 14	1 |- ( A. x ph -> [ y / x ] ph )

Syntax hints:   -> wi 4   A.wal 1241   [wsb 1645

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-4 1400  ax-i9 1423  ax-ial 1427

This theorem depends on definitions:  df-bi 110  df-sb 1646

This theorem is referenced by:  sbh  1659  sbft  1728  pm13.183  2681  spsbc  2775