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Theorem pm5.21ndd 621
Description: Eliminate an antecedent implied by each side of a biconditional, deduction version. (Contributed by Paul Chapman, 21-Nov-2012.) (Revised by Mario Carneiro, 31-Jan-2015.)
Hypotheses
Ref Expression
pm5.21ndd.1  |-  ( ph  ->  ( ch  ->  ps ) )
pm5.21ndd.2  |-  ( ph  ->  ( th  ->  ps ) )
pm5.21ndd.3  |-  ( ph  ->  ( ps  ->  ( ch 
<->  th ) ) )
Assertion
Ref Expression
pm5.21ndd  |-  ( ph  ->  ( ch  <->  th )
)

Proof of Theorem pm5.21ndd
StepHypRef Expression
1 pm5.21ndd.1 . . . 4  |-  ( ph  ->  ( ch  ->  ps ) )
2 pm5.21ndd.3 . . . 4  |-  ( ph  ->  ( ps  ->  ( ch 
<->  th ) ) )
31, 2syld 40 . . 3  |-  ( ph  ->  ( ch  ->  ( ch 
<->  th ) ) )
43ibd 167 . 2  |-  ( ph  ->  ( ch  ->  th )
)
5 pm5.21ndd.2 . . . . 5  |-  ( ph  ->  ( th  ->  ps ) )
65, 2syld 40 . . . 4  |-  ( ph  ->  ( th  ->  ( ch 
<->  th ) ) )
7 bicom1 122 . . . 4  |-  ( ( ch  <->  th )  ->  ( th 
<->  ch ) )
86, 7syl6 29 . . 3  |-  ( ph  ->  ( th  ->  ( th 
<->  ch ) ) )
98ibd 167 . 2  |-  ( ph  ->  ( th  ->  ch ) )
104, 9impbid 120 1  |-  ( ph  ->  ( ch  <->  th )
)
Colors of variables: wff set class
Syntax hints:    -> wi 4    <-> wb 98
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101
This theorem depends on definitions:  df-bi 110
This theorem is referenced by:  pm5.21nd  825  sbcrext  2835  rmob  2850  epelg  4027  eqbrrdva  4505  relbrcnvg  4704  fmptco  5330  ovelrn  5649  brtpos2  5866  brdomg  6229  genpelvl  6610  genpelvu  6611  fzoval  9005  clim  9802
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