Theorem jaob 630

Description: Disjunction of antecedents. Compare Theorem *4.77 of [WhiteheadRussell] p. 121. (Contributed by NM, 30-May-1994.) (Revised by Mario Carneiro, 31-Jan-2015.)

Assertion

Ref	Expression
jaob	|- (((ph \/ ch) -> ps) <-> ((ph -> ps) /\ (ch -> ps)))

Proof of Theorem jaob

Step	Hyp	Ref	Expression
1		ax-io 629	1 |- (((ph \/ ch) -> ps) <-> ((ph -> ps) /\ (ch -> ps)))

Syntax hints:   -> wi 4   /\ wa 97   <-> wb 98   \/ wo 628

This theorem was proved from axioms:  ax-io 629

This theorem is referenced by:  olc  631  orc  632  pm3.44  634  pm4.77  711  pm5.53  714  unss  3111  ralunb  3118  intun  3637  intpr  3638  relop  4429  indstr  8312