Theorem imdistand 421

Description: Distribution of implication with conjunction (deduction rule). (Contributed by NM, 27-Aug-2004.)

Hypothesis

Ref	Expression
imdistand.1	|- ( ph -> ( ps -> ( ch -> th ) ) )

Assertion

Ref	Expression
imdistand	|- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Proof of Theorem imdistand

Step	Hyp	Ref	Expression
1		imdistand.1	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
2		imdistan 418	. 2 |- ( ( ps -> ( ch -> th ) ) <-> ( ( ps /\ ch ) -> ( ps /\ th ) ) )
3	1, 2	sylib 127	1 |- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Syntax hints:   -> wi 4   /\ wa 97

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101

This theorem depends on definitions:  df-bi 110

This theorem is referenced by:  imdistanda  422  pm5.32d  423  fconstfvm  5379  lbzbi  8551