Theorem hbsb3 1689

Description: If y is not free in ph, x is not free in [ y / x ] ph. (Contributed by NM, 5-Aug-1993.)

Hypothesis

Ref	Expression
hbsb3.1	|- ( ph -> A. y ph )

Assertion

Ref	Expression
hbsb3	|- ( [ y / x ] ph -> A. x [ y / x ] ph )

Proof of Theorem hbsb3

Step	Hyp	Ref	Expression
1		hbsb3.1	. . 3 |- ( ph -> A. y ph )
2	1	sbimi 1647	. 2 |- ( [ y / x ] ph -> [ y / x ] A. y ph )
3		hbsb2a 1687	. 2 |- ( [ y / x ] A. y ph -> A. x [ y / x ] ph )
4	2, 3	syl 14	1 |- ( [ y / x ] ph -> A. x [ y / x ] ph )

Syntax hints:   -> wi 4   A.wal 1241   [wsb 1645

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-11 1397  ax-4 1400  ax-i9 1423  ax-ial 1427

This theorem depends on definitions:  df-bi 110  df-sb 1646

This theorem is referenced by:  nfs1  1690  sbcof2  1691  ax16  1694  sb8h  1734  sb8eh  1735  ax16ALT  1739