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Mirrors > Home > ILE Home > Th. List > elabg | Unicode version |
Description: Membership in a class abstraction, using implicit substitution. Compare Theorem 6.13 of [Quine] p. 44. (Contributed by NM, 14-Apr-1995.) |
Ref | Expression |
---|---|
elabg.1 |
Ref | Expression |
---|---|
elabg |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nfcv 2178 | . 2 | |
2 | nfv 1421 | . 2 | |
3 | elabg.1 | . 2 | |
4 | 1, 2, 3 | elabgf 2685 | 1 |
Colors of variables: wff set class |
Syntax hints: wi 4 wb 98 wceq 1243 wcel 1393 cab 2026 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 99 ax-ia2 100 ax-ia3 101 ax-io 630 ax-5 1336 ax-7 1337 ax-gen 1338 ax-ie1 1382 ax-ie2 1383 ax-8 1395 ax-10 1396 ax-11 1397 ax-i12 1398 ax-bndl 1399 ax-4 1400 ax-17 1419 ax-i9 1423 ax-ial 1427 ax-i5r 1428 ax-ext 2022 |
This theorem depends on definitions: df-bi 110 df-tru 1246 df-nf 1350 df-sb 1646 df-clab 2027 df-cleq 2033 df-clel 2036 df-nfc 2167 df-v 2559 |
This theorem is referenced by: elab2g 2689 intmin3 3642 finds 4323 elxpi 4361 ovelrn 5649 indpi 6440 peano5nnnn 6966 peano5nni 7917 peano5setOLD 10065 |
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