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Theorem ax-12 1402
Description: Rederive the original version of the axiom from ax-i12 1398. (Contributed by Mario Carneiro, 3-Feb-2015.)
Assertion
Ref Expression
ax-12  |-  ( -. 
A. z  z  =  x  ->  ( -.  A. z  z  =  y  ->  ( x  =  y  ->  A. z  x  =  y )
) )

Proof of Theorem ax-12
StepHypRef Expression
1 ax-i12 1398 . . . 4  |-  ( A. z  z  =  x  \/  ( A. z  z  =  y  \/  A. z ( x  =  y  ->  A. z  x  =  y )
) )
21ori 642 . . 3  |-  ( -. 
A. z  z  =  x  ->  ( A. z  z  =  y  \/  A. z ( x  =  y  ->  A. z  x  =  y )
) )
32ord 643 . 2  |-  ( -. 
A. z  z  =  x  ->  ( -.  A. z  z  =  y  ->  A. z ( x  =  y  ->  A. z  x  =  y )
) )
4 ax-4 1400 . 2  |-  ( A. z ( x  =  y  ->  A. z  x  =  y )  ->  ( x  =  y  ->  A. z  x  =  y ) )
53, 4syl6 29 1  |-  ( -. 
A. z  z  =  x  ->  ( -.  A. z  z  =  y  ->  ( x  =  y  ->  A. z  x  =  y )
) )
Colors of variables: wff set class
Syntax hints:   -. wn 3    -> wi 4    \/ wo 629   A.wal 1241    = wceq 1243
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-in2 545  ax-io 630  ax-i12 1398  ax-4 1400
This theorem depends on definitions:  df-bi 110
This theorem is referenced by: (None)
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